A jar contains 4 black marbles and 3 red marbles.
Marbles in a jar probability.
A jar contains 24 marbles some are green and others are blue.
The chance is 2 in 5 but after taking one out the chances change.
Find the probability of picking green 4 20 then find the probability of picking blue 5 19.
Finally multiply the probabilities and reduce to get 1 19.
13 is a prime number and 42.
Total number of marbles 23 4 27 marbles p green marble of green marbles of marbles total 4 27 0 148 so the probability is 4 27 which is about a 14 8 chance.
Place the possible card in front of the jar.
Pose questions to the children about each of the jars and the probability of picking certain colored marbles.
Have the children take turns answering the questions and placing the probability cards in front of each jar after each of the questions.
P getting a color other than red p 25 55 455 probability of this happening 3 times in a row is found by 455 455 455 094 example 2.
The total number of marbles in the second jar is 42 marbles and the total number of blue marbles in the jar is 13.
B find probabilities for p bb p br p rb p ww p at least one red p exactly one red.
If a marble is drawn at random from the jar the probability that it is green is 32.
If we got a red marble before then the chance of a blue marble next is 2 in 4.
At least 1 red a jar contains 30 red marbles 12 yellow marbles 8 green marbles and 5 blue marbles.
So the probability of getting a blue marble is 13 42.
What is the probability that you pick 3 green no red 1 of each at least 1 blue marble if a jar contains 5 blue 3 green and 4 red marbles.
Answer in decimal rounded off to 2 decimal places.
Two marbles are drawn without replacement.
For example if the answer is 2 3 the response should be 0 67.
So the next time.
Remember there is one less marble in the jar.